ÒÎÐ 5 ñòàòåé:
Ìåòîäè÷åñêèå ïîäõîäû ê àíàëèçó ôèíàíñîâîãî ñîñòîÿíèÿ ïðåäïðèÿòèÿ
Ïðîáëåìà ïåðèîäèçàöèè ðóññêîé ëèòåðàòóðû ÕÕ âåêà. Êðàòêàÿ õàðàêòåðèñòèêà âòîðîé ïîëîâèíû ÕÕ âåêà
Õàðàêòåðèñòèêà øëèôîâàëüíûõ êðóãîâ è åå ìàðêèðîâêà
Ñëóæåáíûå ÷àñòè ðå÷è. Ïðåäëîã. Ñîþç. ×àñòèöû
ÊÀÒÅÃÎÐÈÈ:
- Àðõåîëîãèÿ
- Àðõèòåêòóðà
- Àñòðîíîìèÿ
- Àóäèò
- Áèîëîãèÿ
- Áîòàíèêà
- Áóõãàëòåðñêèé ó÷¸ò
- Âîéíîå äåëî
- Ãåíåòèêà
- Ãåîãðàôèÿ
- Ãåîëîãèÿ
- Äèçàéí
- Èñêóññòâî
- Èñòîðèÿ
- Êèíî
- Êóëèíàðèÿ
- Êóëüòóðà
- Ëèòåðàòóðà
- Ìàòåìàòèêà
- Ìåäèöèíà
- Ìåòàëëóðãèÿ
- Ìèôîëîãèÿ
- Ìóçûêà
- Ïñèõîëîãèÿ
- Ðåëèãèÿ
- Ñïîðò
- Ñòðîèòåëüñòâî
- Òåõíèêà
- Òðàíñïîðò
- Òóðèçì
- Óñàäüáà
- Ôèçèêà
- Ôîòîãðàôèÿ
- Õèìèÿ
- Ýêîëîãèÿ
- Ýëåêòðè÷åñòâî
- Ýëåêòðîíèêà
- Ýíåðãåòèêà
III. Äèàãíîñòèêà ïåðåæèâàíèé âðåìåííûõ îðèåíòàöèè
Èíñòðóêöèÿ 1. Îöåíèòå ïåðåæèâàíèÿ ñîáûòèé ïðîøëîãî. Ïîñëå ýòîãî îáâåäèòå êðóæêîì âûáðàííûé âàìè îòâåò. Ïîñòàðàéòåñü êàê ìîæíî ðåæå âûáèðàòü îòâåò «Î».
3 – ñîâåðøåííî âåðíî
2 – âåðíî
1 – ïîæàëóé, òàê
0 – ñîãëàñåí ñ îáîèìè óòâåðæäåíèÿìè
Ìîå ïðîøëîå êàæåòñÿ ìíå:
ìåäëåííûì 3 – 2– –0–1–2 – 3 áûñòðûì
ïóñòûì 3 – 2– –0–1–2 – 3 íàñûùåííûì
ïëàâíûì 3 – 2– –0–1–2 – 3 ñêà÷êîîáðàçíûì
ïðèÿòíûì 3 – 2– –0–1–2 – 3 íåïðèÿòíûì
íåïðåðûâíûì 3 – 2– –0–1–2 – 3 ïðåðûâèñòûì
ñæàòûì 3 – 2– –0–1–2 – 3 ðàñòÿíóòûì
îäíîîáðàçíûì 3 – 2– –0–1–2 – 3 ðàçíîîáðàçíûì
îðãàíèçîâàííûì 3 – 2– – 0–1–2 – 3 íåîðãàíèçîâàííûì
öåëüíûì 3 – 2– –0–1–2 – 3 ðàçäðîáëåííûì
áåñïðåäåëüíûì 3 – 2–1–0–1–2 – 3 îðãàíèçîâàííûì
Èíñòðóêöèÿ 2. Îöåíèòå ñâîè ïåðåæèâàíèÿ æèçíè â íàñòîÿùèé ïåðèîä. Ïîñëå ýòîãî îáâåäèòå êðóæêîì âûáðàííûé âàìè îòâåò. Ïîñòàðàéòåñü êàê ìîæíî ðåæå âûáèðàòü îòâåò «0».
3 – ñîâåðøåííî âåðíî
2 – âåðíî
1 – ïîæàëóé, òàê
0 – ñîãëàñåí ñ îáîèìè óòâåðæäåíèÿìè
 íàñòîÿùèé ìîìåíò ìîÿ æèçíü:
òå÷åò ìåäëåííî 3 – 2–1–0–1–2 – 3 òå÷åò áûñòðî
ïóñòàÿ 3 – 2–1–0–1–2 – 3 íàñûùåííàÿ
ïëàâíàÿ 3 – 2–1–0–1–2 – 3 ñêà÷êîîáðàçíàÿ
ïðèÿòíàÿ 3 – 2–1–0–1 – 2 – 3 íåïðèÿòíàÿ
íåïðåðûâíàÿ 3 – 2–1–0–1 – 2 – 3 ïðåðûâèñòàÿ
ñæàòàÿ 3 – 2–1–0–1–2 – 3 ðàñòÿíóòàÿ
îäíîîáðàçíàÿ 3 – 2–1–0–1–2 – 3 ðàçíîîáðàçíàÿ
îðãàíèçîâàííàÿ 3 – 2–1–0–1–2 – 3 íåîðãàíèçîâàííàÿ
öåëüíàÿ 3 – 2 – 1–0–1–2 – 3 ðàçäðîáëåííàÿ
áåñïðåäåëüíàÿ 3 – 2–1–0–1 – 2 – 3 îãðàíè÷åííàÿ
Èíñòðóêöèÿ 3. Îöåíèòå ñîáûòèÿ áóäóùåãî. Ïîñëå ýòîãî îáâåäèòå êðóæêîì âûáðàííûé âàìè îòâåò. Ïîñòàðàéòåñü êàê ìîæíî ðåæå âûáèðàòü îòâåò «0».
3 – ñîâåðøåííî âåðíî
2 – âåðíî
1 – ïîæàëóé, òàê
0 – ñîãëàñåí ñ îáîèìè óòâåðæäåíèÿìè
Ìîå áóäóùåå êàæåòñÿ ìíå:
ìåäëåííûì 3 – 2– –0–1–2 – 3 áûñòðûì
ïóñòûì 3 – 2– –0–1 – 2 – 3 íàñûùåííûì
ïëàâíûì 3 – 2– –0–1 – 2 – 3 ñêà÷êîîáðàçíûì
ïðèÿòíûì 3 – 2– –0–1–2 – 3 íåïðèÿòíûì
íåïðåðûâíûì 3 – 2– –0–1 – 2 – 3 ïðåðûâèñòûì
ñæàòûì 3 – 2– – 0 – 1 – 2 – 3 ðàñòÿíóòûì
îäíîîáðàçíûì 3 – 2– –0–1–2 – 3 ðàçíîîáðàçíûì
îðãàíèçîâàííûì 3 – 2– –0–1–2 – 3 íåîðãàíèçîâàííûì
öåëüíûì 3 – 2–1–0–1–2 – 3 ðàçäðîáëåííûì
áåñïðåäåëüíûì 3 – 2–1–0–1–2 – 3 îãðàíè÷åííûì
Íå íàøëè, ÷òî èñêàëè? Âîñïîëüçóéòåñü ïîèñêîì: